![]() ![]() I have no idea where I got the 60 gal figure.At 15 gal of course your times will be a lot less.ġ5 gal = 2 cubic foot as standard psi = 20 cubic 30 psi = 4 cubic feetĪt 7.6 drain rate - a little over 2 minutes The smaller sprayer will of course work for longer. Being drained at a rate of 13scfm says that it will work for about 5 minutes before having to stop and recharge - it will take longer to drain if the compressor runs while this is happening since you're putting 5.4 back in for every minute you're taking 13 out - the net drain is only 7.6scfm so about 8 minutes before the compressor cannot keep up. one atmosphere is about 15psi so if we assume a 150psi charge on the tank - that is 80 scf of air to start with - the 16scf vol 30 psi or 64scf to work with. What you have is 60 gallons at some reserve pressure - that is what determines the number of standard cubic feet of air you have to start with (and a "standard cubic foot of air" is always the same regardless of pressure - it only takes up a cubic foot at sea level - it's defined that way)Ħ0 gal = 8 cubic feet (give or take a bit). The out put at 30 psi will not be much different, some, but nothing like triple. Feel free to elaborate f you feel the need.īillThe main thing you skipped was the fact that 5.4scfm was all his compressor can suck in at the speed it runs while outputting 100 psi. ![]() ![]() I also know that V is not a rate in the Ideal Gas law but it works. V2= 18 cfm is the maximum your compressor will output at 30 psi.įor all you other engineers out there: Yes I know I skipped a bunch of steps and made a bunch of assumptions. We want to know V (cfm) at a different P (30 psi) ![]()
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